Hi
I am a fan of the quatloos casino gambling page (https://www.quatloos.com/quatloosia-goo ... amble2.htm) - it shows clearly the madness of gambling. I was going to share it - but I can't get my head around the maths - my bad probably. Quote:
"Your chances of leaving the Roulette table a winner are determined by calculating your Payout Percentage to the power of the Number of Wins You Need to Get Ahead. Thus,
Behind 1 Bet 89.48% 89.48%
Behind 2 Bets 89.48% x 89.48% 80.07%
Behind 3 Bets 89.48%^3rd 51.33%
Behind 4 Bets 89.48%^4th 6.94%
Behind 5 Bets 89.48%^5th 0.00%
What this means is that on your first spin you have a 89.48% chance of walking away a winner. If you lose that spin, you have a 80.07% chance of walking away even, but after getting down 3 bets only a 51.33% chance of walking away a winner. If you are down four betting units, you have a small 6.94% chance of beating the House, and after you are down 5 bets you are toast (statistically you can't win).Since the House's 5.26% advantage means that it should win an "extra" over you ever 19 spins, this means that by at least the 95th spin (19 x 5), the House knows you will be a loser."
But 89.48%^5 is 57.3 The quatloos calculation works on the "Behind 2 bets" example, but "Behind3 bets" is 71%, not 51(?)
Any help gratefully received!
help with the quatloos casino gambling maths please...
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Re: help with the quatloos casino gambling maths please...
That was written a long time ago, and at this point I couldn't even tell you who wrote it. Sorry. As you can tell from the rest of the board, that is not what we do.
"A wise man proportions belief to the evidence."
- David Hume
- David Hume